Re: Division of two complex numbers

Le 20/01/2025 à 16:22, Richard Hachel  a écrit :

Le 20/01/2025 à 15:46, Moebius a écrit :

Am 20.01.2025 um 12:02 schrieb Richard Hachel:

Division of two complex numbers.
 Now let's set Z = (a + ib)/(a' + ib')

 I guess you meant: Z = z1/z2
 

with
z1 = a + ib
and
z2 = a' + ib'
 What becomes of Z = A + iB?

 

See here:  https://en.wikipedia.org/wiki/Complex_number#Complex_conjugate,_absolute_value,_argument_and_division

  Merci beaucoup.
  I saw this.
  <http://nemoweb.net/jntp?EAsBh7E4-FgqHBbEPrgfaV9LEbI@jntp/Data.Media:1>
  Merci, je vais donc pouvoir répondre aux mathématiciens.
  R.H.

As I expected, it is completely wrong.
The same sign error.
Mathematicians give:
z1/z2=[(aa'+bb')/(a'²+b'²)]+i[(ba'-ab')/(a'²+b'²)]
It was necessary to write:
z1/z2=[(aa'-bb')/(a'²-b'²)]+i[(ba'-ab')/(a'²-b'²)]
Three sign errors (which is the same error) because each time we put i²=-1 where b and b' are already defined.
R.H.