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On 20.01.2025 15:22, FromTheRafters wrote:But there are no Natual Numbers without Aleph_0 successors.WM explained :It says that all natural numbers without ℵ₀ successors can be handled. This is different for definable natural numbers because there not all natural numbers can be handled:On 19.01.2025 13:32, Richard Damon wrote:>
>Note, even in actual infinity, every Natural Number has Aleph_0 successors>
Then not all could be subtracted from ℕ. But that is possible ℕ \ {1, 2, 3, ...} = { }.
All that really says is that the difference set between the set of natural numbers and the set of natural numbers is empty.
∀n ∈ ℕ_def: |ℕ \ {1, 2, 3, ..., n}| = ℵo
Regards, WM
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