Re: Division of two complex numbers

ooops - typo!  >
  So we get: (0, 1)^2 ) 0^2 + 2*(0 - 1) + 1 = 0 + (-2) + 1 = -1 .                     ^   So we get: (0, 1)^2 = ...
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For R.H.
  By the binominal formulas we have: (a, b)^2 = a^2 + 2ab + b^2
  So we get: (0, 1)^2 ) 0^2 + 2*(0 - 1) + 1 = 0 + (-2) + 1 = -1  Enjoy...

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