Sujet : Re: x²+4x+5=0
De : chris.m.thomasson.1 (at) *nospam* gmail.com (Chris M. Thomasson)
Groupes : sci.mathDate : 23. Jan 2025, 04:04:56
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <vmsbkp$1b59e$1@dont-email.me>
References : 1 2
User-Agent : Mozilla Thunderbird
On 1/22/2025 3:58 PM, sobriquet wrote:
Op 22/01/2025 om 14:48 schreef Richard Hachel:
x²+4x+5=0
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This equation has no root, and it never will.
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We can then find two roots of its mirror curve.
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Let x'=-3 and x"=-1
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These are not roots of this curve, but the roots of the imaginary mirror curve.
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What is this imaginary mirror curve?
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It is the curve with equation y=-x²-4x-3
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Let's look for its roots, and we find x'=-3 and x'=-1
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These are the imaginary roots of x²-4x+5.
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Or x'=-3(i) and x'=-1(i)
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R.H.
Wolfram Alpha tells us there are two roots:
https://www.wolframalpha.com/input?i=solve+x%5E2%2B4x%2B5%3D0
Here you can see the roots:
https://www.desmos.com/3d/mpwj5h2ab8
The roots are fun to work with in a Julia fractal. They can plot many things. An example, my multi julia:
https://paulbourke.org/fractals/multijulia