Sujet : Re: Forgotten to answer?
De : wolfgang.mueckenheim (at) *nospam* tha.de (WM)
Groupes : sci.mathDate : 26. Jan 2025, 15:14:36
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <vn5g0c$3qu1c$2@dont-email.me>
References : 1 2 3 4 5 6 7 8 9 10 11 12 13
User-Agent : Mozilla Thunderbird
On 26.01.2025 14:04, FromTheRafters wrote:
After serious thinking WM wrote :
On 26.01.2025 10:08, FromTheRafters wrote:
WM wrote :
On 25.01.2025 18:03, FromTheRafters wrote:
WM pretended :
On 22.01.2025 19:01, Python wrote:
>
> If you have three coins of 2 euros not a single one is "necessary" to
pay a 3 euros drink
>
This failing analogy has been repeated again an again, first by Rennenkampff, because their authors do not understand the principle: Cantor's theorem concerns the set of indices or ordinal numbers, not a set of sets.
>
Then how are these 'Cantor's Theorem' ordinals contructed?
>
That can be done in an arbitrary way.
>
Arbitrarily constructed ordinals? Tell me more!
>
Which of {a, b}, {b, c}, {c, a} are required for the union {a, b, c}?
>
Indexing: 1. {a, b}, 2. {b, c}, 3. {c, a}.
>
The first set is not required because
>
{a, b, c} = {a, b} U {b, c} U {c, a} = {b, c} U {c, a}.
>
The second set is the first required one because
>
{a, b, c} = {b, c} U {c, a} =/= {c, a}.
>
Therefore Cantors's theorem supplies the set of ordinals {2, 3}.
>
By the way, every other choice of indices would yield the same Cantor-set {2, 3}.
I see set manipulations but no ordinals at all, arbitrary or not.
The ordinals of necessary sets are 2 and 3. The first necessary ordinal is 2.
Regards, WM