Liste des Groupes | Revenir à s math |
On 1/31/25 5:21 AM, WM wrote:
From this set O every finite subset can be subtracted without changing the result. Therefore, by induction, no finite A(n) remains. Therefore the set O has no first ordinal. Therefore it is not a set of ordinals. Therefore your claim is wrong.
Induction doesn't work that way.It works that way: When n belongs to ℕ, then n+1 belongs to ℕ.
There is no requirement that a "minimal" set exists.There is the assumption that a set with U(A(n)) = ℕ exists. No element remains. The set does not exist.
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