Sujet : Re: Primitive Pythagorean Triples
De : qnivq.ragjvfgyr (at) *nospam* ogvagrearg.pbz (David Entwistle)
Groupes : sci.mathDate : 02. Feb 2025, 10:45:16
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <vnnerb$khvr$1@dont-email.me>
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On Sat, 1 Feb 2025 10:54:50 -0000 (UTC), Alan Mackenzie wrote:
There are lots. The smallest "non-trivial" example has a hypotenuse of
65. We have (16, 63, 65) and (33, 56, 65). The next such has a
hypotenuse of 85: (36, 77, 85) and (13, 84, 85).
In general, a hypotenuse in a Pythagorean triple has prime factors of
the form (4n + 1), together with any number of factors 2, and squares of
other prime factors. The latter two things don't really add much of
interest.
If the hypotenuse is a prime number (4n + 1), there is just one triple
with it. If there are two distinct factors of the form (4n + 1), there
are two triples (as in 5 * 13 and 5 * 17 above). The more such prime
factors there are in the hypotenuse, the more triples there are for it,
though it's not such a simple linear relationship that one might expect.
Hi Alan,
Thanks for the comprehensive reply. I see where I have gone wrong - I was
looking at hypotenuse that were prime, when I should have been looking for
co-prime with the other two sides. I'll correct that and see where it
takes me.
Best wishes,
-- David Entwistle