Sujet : Re: x²+4x+5=0
De : r.hachel (at) *nospam* tiscali.fr (Richard Hachel)
Groupes : sci.mathDate : 03. Feb 2025, 00:57:38
Autres entêtes
Organisation : Nemoweb
Message-ID : <bAEs3Q8MJBL33POSW9beO-OYiI0@jntp>
References : 1 2 3
User-Agent : Nemo/1.0
Le 02/02/2025 à 23:55, "Chris M. Thomasson" a écrit :
On 1/23/2025 2:51 AM, Peter Fairbrother wrote:
On 22/01/2025 13:48, Richard Hachel wrote:
x²+4x+5=0
>
This equation has no root, and it never will.
-3.6180339887499
-1.3819660112501
-2-1i
-2+1i
The two roots have non-zero imaginary parts, so they are not reals.
(-2-1i)²+4(-2-1i)+5 = 0
(-2+1i)²+4(-2+1i)+5 = 0
:^)
This is obviously very true.
But it poses a small problem for me that I can't quite explain.
I'll think about that.
R.H.
x²+4x+5=0
Re: x²+4x+5=0