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On 06.02.2025 19:54, Jim Burns wrote:No. N is exactly the set of all, and only the natural numbers.On 2/6/2025 11:55 AM, WM wrote:Then it is the collection ℕ_def of definable numbers.On 06.02.2025 15:57, Jim Burns wrote:The set ℕ₁ is described as having induction valid for it.The key is that ∀ᴺ¹n: ∃ᴺ¹j′: n<j′The key is that the set ℕ is created by induction.Then it is the set ℕ of all natural numbers.
Sets missing natural numbers and sets with extra, non.inducible,
un.natural numbers are not ℕ₁
You contradict yourself.
Tautologically.Which is curious, when one considers that ℕ₁ appears nowhere in it.The axiom of induction holds for all predicates P which satisfy
induction.
If the set M is described as the smallest set satisfying F(1) ∈ M andWrong. M cannot be finite.
F(n) ∈ M ==> F(n+1) ∈ M then M contains all FISONs which can be
subtracted from U(Fn)) without changing the assumed result ℕ.
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