Sujet : Re: The set of necessary FISONs
De : james.g.burns (at) *nospam* att.net (Jim Burns)
Groupes : sci.mathDate : 07. Feb 2025, 17:10:40
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <6b0e16a0-a9a6-4cc2-97d8-61c560dd7eab@att.net>
References : 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
User-Agent : Mozilla Thunderbird
On 2/6/2025 2:32 PM, WM wrote:
On 06.02.2025 19:54, Jim Burns wrote:
On 2/6/2025 11:55 AM, WM wrote:
On 06.02.2025 15:57, Jim Burns wrote:
The key is that ∀ᴺ¹n: ∃ᴺ¹j′: n<j′
>
The key is that
the set ℕ is created by induction.
>
The set ℕ₁ is described as having induction valid for it.
>
Then it is the collection ℕ_def of definable numbers.
>
Sets missing natural numbers and
sets with extra, non.inducible, un.natural numbers
are not ℕ₁
>
Then it is the set ℕ of all natural numbers.
>
You contradict yourself.
No.
One set is both
the emptiest superset ⋃{F} of each FISON and
the fullest set ⋂𝒫ⁱⁿᵈ common to all inductive sets.
----
⎛ The fullest set ⋂ℐ common to a set ℐ of inductive sets
⎜ is inductive.
⎜
⎜ For each inductive set 𝕂, there is
⎜ an inductive set ⋂𝒫ⁱⁿᵈ(𝕂) common to
⎜ all that set's inductive subsets 𝒫ⁱⁿᵈ(𝕂)
⎜
⎜ For each two inductive sets 𝕂 and 𝕄
⎜ ⋂𝒫ⁱⁿᵈ(𝕂) = ⋂𝒫ⁱⁿᵈ(𝕄) = ⋂𝒫ⁱⁿᵈ
⎜
⎜ (Inductive) ⋂𝒫ⁱⁿᵈ is
⎜ the fullest set common to all inductive sets.
⎜
⎝ If 𝕏 is inductive, then ⋂𝒫ⁱⁿᵈ ⊆ 𝕏
⎛ 0 ∈ ⋃{F}
⎜ k ∈ ⋃{F} ⇒ k+1 ∈ ⋃{F}
⎜ ⋃{F} is inductive.
⎜
⎝ ⋂𝒫ⁱⁿᵈ ⊆ ⋃{F}
⎛ No element of any FISON is not.in ⋂𝒫ⁱⁿᵈ
⎜
⎜ No element of ⋃{F} is not.in ⋂𝒫ⁱⁿᵈ
⎜
⎝ ⋃{F} ⊆ ⋂𝒫ⁱⁿᵈ
⎛ ⋂𝒫ⁱⁿᵈ ⊆ ⋃{F}
⎜
⎜ ⋃{F} ⊆ ⋂𝒫ⁱⁿᵈ
⎜
⎝ ⋂𝒫ⁱⁿᵈ = ⋃{F}