Re: The set of necessary FISONs

On 2/16/25 12:16 PM, WM wrote:

On 16.02.2025 13:34, Richard Damon wrote:

On 2/16/25 5:39 AM, WM wrote:

On 15.02.2025 18:54, joes wrote:

No element of the set of FISONs is
necessary

>
Therefore all can be removed, and U(F) = ℕ ==> U(F\F) = ℕ.
>

Which just proves there is no necesary set.

 Induction proves that there is no FISON that, when removed, changes the premise. Therefore all FISONs can be removed without changing the premise. The conclusion is U(F\F) = ℕ.
 Regards, WM

Just because there is not individual FISON that when removed changes the results, doesn't mean that you can remove ALL.
For Any and For All are different operations in infinite sets, something your Naive Logic can't handle.
And you continued repeating it, shows that you are to stupid to understand your own stupidity.