Re: The set of necessary FISONs

On 20.02.2025 21:13, joes wrote:

Am Thu, 20 Feb 2025 18:50:27 +0100 schrieb WM:

∀n ∈ ℕ: n+1 ∈ ℕ. Together with 1 ∈ ℕ this defines the set ℕ. (*)
Addition of all numbers defined by (*) to the empty set is tantamount to
addition of ℕ to the empty set.

Absolutely not.

What is missing?

That would be {N}

Gibberish. ℕ is a set. ℕ = {1, 2, 3, ...}. If all numbers are added to { }, then ℕ is complete, not {ℕ}, a set which contains ℕ.
Regards, WM