Re: y=f(x)=(x²)²+2x²+3

Liste des GroupesRevenir à s math 
Sujet : Re: y=f(x)=(x²)²+2x²+3
De : invalid (at) *nospam* example.invalid (Moebius)
Groupes : sci.math
Date : 22. Feb 2025, 00:15:02
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <vpb1dm$3k2fb$1@dont-email.me>
References : 1 2 3 4 5 6 7 8 9 10
User-Agent : Mozilla Thunderbird
Am 07.02.2025 um 20:45 schrieb Python:

In addition to be a crank you have absolutely no intellectual integrity.
Talking about Mückenheim? :-o

Date Sujet#  Auteur
6 Feb 25 * y=f(x)=(x²)²+2x²+321Richard Hachel
6 Feb 25 `* Re: y=f(x)=(x²)²+2x²+320sobriquet
6 Feb 25  `* Re: y=f(x)=(x²)²+2x²+319Richard Hachel
6 Feb 25   `* Re: y=f(x)=(x²)²+2x²+318sobriquet
6 Feb 25    +* Re: y=f(x)=(x²)²+2x²+34Chris M. Thomasson
6 Feb 25    i+- Re: y=f(x)=(x²)²+2x²+31FromTheRafters
7 Feb 25    i`* Re: y=f(x)=(x²)²+2x²+32Richard Hachel
7 Feb 25    i `- Re: y=f(x)=(x²)²+2x²+31FromTheRafters
6 Feb 25    `* Re: y=f(x)=(x²)²+2x²+313Richard Hachel
6 Feb 25     +- Re: y=f(x)=(x²)²+2x²+31Python
7 Feb 25     `* Re: y=f(x)=(x²)²+2x²+311sobriquet
7 Feb 25      `* Re: y=f(x)=(x²)²+2x²+310Richard Hachel
7 Feb 25       +* Re: y=f(x)=(x²)²+2x²+38Alan Mackenzie
7 Feb 25       i+* Re: y=f(x)=(x²)²+2x²+34Richard Hachel
7 Feb 25       ii`* Re: y=f(x)=(x²)²+2x²+33Python
7 Feb 25       ii +- Re: y=f(x)=(x²)²+2x²+31Richard Hachel
22 Feb 25       ii `- Re: y=f(x)=(x²)²+2x²+31Moebius
7 Feb 25       i+- Re: y=f(x)=(x²)²+2x²+31Richard Hachel
22 Feb 25       i`* Re: y=f(x)=(x²)²+2x²+32Moebius
22 Feb 25       i `- Re: y=f(x)=(x²)²+2x²+31Alan Mackenzie
7 Feb 25       `- Re: y=f(x)=(x²)²+2x²+31sobriquet

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