Re: New equation

Le 02/03/2025 à 18:10, Python a écrit :

Le 02/03/2025 à 17:32, Richard Hachel a écrit :

Le 02/03/2025 à 06:06, Jim Burns a écrit :
 ⎜

(a+b𝑖)+(c+d𝑖) = (a+c)+(b+d)𝑖

>
 Yes.
>

(a+b𝑖)⋅(c+d𝑖) = (ac-bd)+(ad+bc)𝑖

>
 No.
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 (a+b𝑖)⋅(c+d𝑖) = (ac+bd)+(ad+bc)𝑖
>
>
 In all thing : (a+b𝑖)⋅(c+d𝑖) = (ac+bd)+(ad+bc)𝑖
>

 This is true in R(j) not in C.
 I posted about this yesterday. Did you even read my post?
 

He probably read it and did not understand a single word :)
--
F.J.