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On 3/6/2025 3:54 AM, WM wrote:It defines Z₀ precisely.Am 06.03.2025 um 02:52 schrieb Jim Burns:<<JB<WM>>>I think that you (WM) are using a different dictionary.>
I think that you (JB) should correct your statement:<</JB<WM>>>>>
You need not the intersection however because
Z₀ can also be defined by
{ } ∈ Z₀, and
if {{{...{{{ }}}...}}} with n curly brackets ∈ Z₀
then {{{...{{{ }}}...}}} with n+1 curly brackets ∈ Z₀.
No.
No BECAUSE
that doesn't DEFINE Z₀
What does your inductive description permit in Z₀Induction excludes Bob. He is not in the empty set and not in the set containing the empty set and not in any set with more curly brackets.
which should not be permitted in Z₀ ?
Anything.
Your description permits Bob, as long as
{Bob}, {{Bob}}, {{{Bob}}}, ... are also in Z₀
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