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Richard Hachel <r.hachel@tiscali.fr> wrote:
Then i = (I guess) = i^1 = -1, one might think.I recall the idea: the imaginary number i is a unit such that it is
invariant whatever its power. For all x, we have i^x = -1.
So again a contradiction (since 1 =/= -1).This was already the case with the real unit n=1. For all x, 1^x=1.And for all x apart from 0, x^0 = 1. That includes i^0 = 1.
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