Re: New way of dealing with complex numbers

Le 08/03/2025 à 14:18, Richard Hachel a écrit :

Le 08/03/2025 à 12:47, efji a écrit :

Le 08/03/2025 à 12:08, Python a écrit :

 

the total delirium he is now stuck on (i^x=-1 for all x).

 

Pathetic idiot...

 To me, i is that imaginary unit with a mathematical property such that i^x=-1.
 i=-1
i²=-1
i².i=-1
i².i²=-1

Again, learn once for all what "associativity" means!
Associativity is MANDATORY to be able to write something like i^4 = i*i*i*i.
For a non associative operator, i^4 means NOTHING.
For an associative operator,
i^4 = i*i*i*i = (i*i)*(i*i) = i*i^3 = (i^2)*i*i etc.
Then, if you assume i^2=-1 you MUST have i^4 = (i^2)^2 = (-1)^2 = 1
End of the story, and then you shut the fuck up forever on the subject.
Thanks
--
F.J.