Sujet : Re: The splendor of true
De : chris.m.thomasson.1 (at) *nospam* gmail.com (Chris M. Thomasson)
Groupes : sci.mathDate : 10. Mar 2025, 10:19:50
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <vqmarn$19276$1@dont-email.me>
References : 1 2 3 4 5
User-Agent : Mozilla Thunderbird
On 3/10/2025 1:33 AM, efji wrote:
Le 10/03/2025 à 03:03, Chris M. Thomasson a écrit :
>
Indeed. Sorry for the stupid question, but the following parts of RH's description:
>
Z=aa'+bb'+i(ab'+a'b) and not Z=aa'-bb'+i(ab'+a'b).
>
Means a = x component, b = y component, right? ;^o
Well...
In his disturbed mind, (a,b) = a-b on the x axis :)
But forget the pathetic egotic and just try a+jb=(a,b) un R^2 with the rule (a+ib)*(a'+jb') = aa'+bb'+j(ab'+a'b) which is the rule on the split-complex set, (thus j^2=1).
Here is what I got for my little test:
https://i.ibb.co/WWwhqh9K/image.pngOh how fun!
The splendor of true
Re: The splendor of true