Re: The Reimann "Zeta" function: How can it ever converge?

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Sujet : Re: The Reimann "Zeta" function: How can it ever converge?
De : FTR (at) *nospam* nomail.afraid.org (FromTheRafters)
Groupes : sci.math
Date : 25. Mar 2025, 21:58:28
Autres entêtes
Organisation : Peripheral Visions
Message-ID : <vrv5dn$5b7d$1@dont-email.me>
References : 1
User-Agent : MesNews/1.08.06.00-gb
Kenny McCormack was thinking very hard :
So I was reading in Wikipedia about the Zeta function, which is defined as:
>
    Z(s) = 1/(1**s) + 1/(2**s) + 1/(3**s) + ...
>
Both the domain and range are specified as the complex numbers.
>
And it says that if s is a negative integers (-2, -4, -6, etc), then Z(s)
is zero.  But that can't be right.  But first, a little manipulation:
>
Suppose s is -2:
>
    1/(n**s), where s = -2
>
is:
>
    1/(1/(n**2))
>
is:
>
    n**2
>
so, the sum is like:
>
    1+4+9+16+25+...
>
Which just grows without bounds.  And is certainly never zero.
>
So, is Wikipedia wrong?  Or just a typo?
It refers to the trivial zeroes of the function. I don't get the double asterisk's meaning.

Date Sujet#  Auteur
25 Mar 25 * The Reimann "Zeta" function: How can it ever converge?5Kenny McCormack
25 Mar 25 +* Re: The Reimann "Zeta" function: How can it ever converge?3efji
26 Mar 25 i`* Thanks! (Was: The Reimann "Zeta" function: How can it ever converge?)2Kenny McCormack
26 Mar 25 i `- Re: Thanks! (Was: The Reimann "Zeta" function: How can it ever converge?)1FromTheRafters
25 Mar 25 `- Re: The Reimann "Zeta" function: How can it ever converge?1FromTheRafters

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