Sujet : Re: Thanks! (Was: The Reimann "Zeta" function: How can it ever converge?)
De : FTR (at) *nospam* nomail.afraid.org (FromTheRafters)
Groupes : sci.mathDate : 26. Mar 2025, 10:50:42
Autres entêtes
Organisation : Peripheral Visions
Message-ID : <vs0ill$1g5m6$1@dont-email.me>
References : 1 2 3
User-Agent : MesNews/1.08.06.00-gb
Kenny McCormack submitted this idea :
In article <vrv5ci$3rj4$1@dont-email.me>, efji <efji@efi.efji> wrote:
...
I think it is far beyond the scope of this group, but let's try :
>
Interesting. I didn't think this group would shy away from this. Seemed
right up your alley, if nothing else.
>
The Riemann zeta function (please, Riemann and not Reimann...) is defined as the following series for any complex s such that Re(s) > 1:
Z(s) = 1/(1**s) + 1/(2**s) + 1/(3**s) + ..
>
Got it. Thanks. The point is that the series expansion only works for
Re(s) > 1. One has to use one of the more complicated expressions for
other input values. Note: This is there in Wikipedia; I must have glossed
over it.
>
Again, thanks for your long and very helpful explanation.
>
P.S. (to the other responder on this thread). ** means exponentiation in
many (but not all) computer languages (*). Maybe I should have written
pow(...) instead, but the point is that there is no clear-cut, 7 bit ASCII
representation for superscripting notation on Usenet. I did the best I
could.
>
(*) Some other languages use ^, but in most/all C-like languages, that
means bitwise XOR.
Thanks, I'm not a programmer. The familiar ASCII caret for superscript, and underline for subscript. I should have just figured what it meant from context but the exponent symbol didn't give me the 'feeling' I get from the double inversion or rather reciprocal.