Sujet : Re: How? ? ?
De : chris.m.thomasson.1 (at) *nospam* gmail.com (Chris M. Thomasson)
Groupes : sci.mathDate : 02. Apr 2025, 21:18:18
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <vsk62b$2kpbg$5@dont-email.me>
References : 1 2 3 4 5
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On 4/2/2025 1:14 PM, Chris M. Thomasson wrote:
On 4/2/2025 1:11 PM, efji wrote:
Le 02/04/2025 à 21:53, Chris M. Thomasson a écrit :
On 4/2/2025 5:49 AM, efji wrote:
Le 02/04/2025 à 14:32, Richard Hachel a écrit :
How can mathematicians come up with such absurdities?
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https://www.youtube.com/watch?v=XZriBHTNPw0
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No mathematician would write \sqrt{i} because the symbol "\sqrt" designs the positive square root of a real number, which does not make sense in \C since it is not an ordered set and the word "positive" is a nonsense in \C.
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Anyway, "i" has 2 square roots : ±(1+i)/\sqrt{2}
and "-i" too : ±(1-i)/\sqrt{2}
Thus, the mathematically wrong expression "\sqrt{i}+\sqrt{-i}" is non univoque and could be any of these 4 values :
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±\sqrt{2}, ±i\sqrt{2}
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You're welcome
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sqrt(0+1i) has two roots:
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[0] = sqrt(0+1i)
[1] = -sqrt(0+1i)
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any of them raised to the the 2'nd power equals 0+1i.
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wow, the dumb Hachel has got a dumb cousin :)
Huh? I don't think you know what you are talking about.
(sqrt(0+1i))^2 = 0+1i
(-sqrt(0+1i))^2 = 0+1i
Got it? Wow.
Keep in mind that 0+1i = i
:^)