Re: Einstein's Mistakes

Den 22.10.2024 04:46, skrev rhertz:

Dr. Serber, 2nd. in command after Oppenheimer, CLEARLY AFFIRMED (in his
1992 book, published once he got a security clearance) that the atomic
bomb WAS COMPLETELY UNRELATED WITH RELATIVITY AND E=mc^2.

 He WROTE "Los Alamos Primer" in 1943, to teach recruited scientists
about the power behind atom fission, and MADE CALCULATIONS that were
present in the booklet, giving results close to 170 MeV of KE plus some
radiation. And the calculations were done by using COULOMB'S FORCES in
electrostatic repulsion, once two (or more) new heavy elements were
produced in the atom fission.

Of course there are Coulomb forces that accelerate the parts of
the atom in a fission.
And you know that this _confirms_ E = mc² because:
One possible fission process is:
1n + U-235 → Ba-141 + Kr-92 + 3n
The atomic weight of these are well known
Left side:
1n      1.008664  u
U-235 235.0439299 u
-------------------
       236.0525939 u
Right side:
Ba-141   140.914412 u
Kr-92     91.926156 u
3n         3.025992 u
---------------------
          235.866560 u
Lost mass: 0.1860339 u
Generally:
In a fission the mass of the constituents is less than
the mass of the fissioned atom.
------------------
All physicists knew that in 1939, obviously.
https://www.atomicarchive.com/resources/documents/beginnings/nature_meitner.html
Quote:
"It seems therefore possible that the uranium nucleus has only small
  stability of form, and may, after neutron capture, divide itself
  into two nuclei of roughly equal size (the precise ratio of sizes
  depending on finer structural features and perhaps partly on chance).
  These two nuclei will repel each other and should gain a total kinetic
  energy of c. 200 Mev., as calculated from nuclear radius and charge."
Meitner calculated from the electrostatic repulsion that
the kinetic energy of the constituents would be ca 200 Mev.
Quote:
  "This amount of energy may actually be expected to be available
  from the difference in packing fraction between uranium and the
  elements in the middle of the periodic system."
'Packing Fraction' is defined as:
((atomic mass - atomic number)/(atomic number))1e4
So when you know the 'packing fraction' of an element,
you can find the 'mass defect' (atomic mass - atomic number).
When an element A is split into two elements B and C,
and you know the packing fractions of all of them,
the difference in packing fraction between A vs B and C
makes is possible to calculate the change in mass:
(mass of A) - ((mass of B)+(mass of C))
When Meitner found that this mass difference was equivalent to
ca.200 Mev it could only be through E = mc².
You know this, because I told you 5 years ago.
So why do you pretend to be ignorant of the fact that all physicists
(and chemists) at the time took E = mc² for granted?
--
Paul
https://paulba.no/