Sujet : Re: [SR] The traveler of Tau Ceti
De : r.hachel (at) *nospam* tiscali.fr (Richard Hachel)
Groupes : sci.physics.relativityDate : 19. Mar 2024, 21:41:21
Autres entêtes
Organisation : Nemoweb
Message-ID : <oaUZj2Vqx_XIyisVSLVjzhx15P8@jntp>
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Le 19/03/2024 à 20:44, "Paul B. Andersen" a écrit :
The problem then consists of determining the instantaneous observable velocity (Voi) at the moment when the rocket will cross Tau Ceti,
What's the point with inventing an apparent (not real)
"observable velocity" which is less than c when you know
that the real velocity according to your theory is > c?
The acceleration of the rocket is a in the rocket's frame of reference, and it will always be the same as the rocket progresses.
Breathe, breathe out, breathe...
It's so obvious that I wonder how you can argue with it.
Imagine your rocket at rest in a frame of reference Vo=0.6c, and another at rest in a frame of reference Vo=0.8c, accelerate the two rockets according to a=10m/s².
There is NO difference. There is no absolute reference.
It comes from this that whatever the instantaneous speed of the rocket, it is at rest in this frame of reference whatever the speed reached.
Always, and for itself, it will accelerate with a constant acceleration in the frame of reference where it will be found.
It is only for the terrestrial observer that the acceleration will be relative and that the rocket will appear to accelerate less and less quickly (it will never exceed Vo=c).
and its instantaneous acceleration measured in the terrestrial reference frame.
The coordinate acceleration in the terrestrial frame is obviously a.
In rocket frame : always a=1.052 ly.y²
In the terrestrial frame : <
http://news2.nemoweb.net/jntp?oaUZj2Vqx_XIyisVSLVjzhx15P8@jntp/Data.Media:1>
R.H.