Re: The problem of relativistic synchronisation

Den 24.08.2024 13:28, skrev Richard Hachel:

I recall the terrible deformities of Minkowskian relativity in the face of what Dr. Hachel says, if we take for example the example of Hachel's Tau Ceti traveler (we send a rocket with an acceleration of 10m/s² to Tau Ceti to travel the 12 light years that separate us from the star), we have in Minkowski mode a proper time of about 3.5 years, against 4,776 years in Hachel.

SR:     τ =  3.304 years
Newton: τ = 11.400 years
Hachel: τ =  4,776 years? Did you mean 4.776 years?
In any case, this is obviously impossible in the real world,
and can never be verified.
So why not use a scenario which is possible in the real word?
Consider this variant of the Langewin's paradox:
------------------------------------------------
The triplets Ginette, Elise and Wanda are co-located on
the equator. They all have an atomic clock.
Ginette is always stationary on the Equator.
Elise is travelling eastwards at low altitude in an aeroplane.
Wanda is travelling westwards at low altitude in an aeroplane.
Both are travelling once around Earth at equator.
Note that the altitude is so low that the gravitational
blue shift can be ignored.
 From the time they are co-located, to they again are co-located
after Elise's and Wanda's journey, Ginette's clock shows that
the duration of their journey is τ_G = two sidereal days.
Please find what the duration of the journey will be
measured by Elise and Wanda, τ_E and τ_W.
Some data:
Circumference of Earth at equator L = 40075 km
Sidereal day Tday = 86164.0905 s
Ginette's speed in the non rotating Earth centred frame of reference (ECI frame), v = L/Tday = 465.1 m/s
SR predicts:  τ_E − τ_G = −259.2 ns,  τ_W − τ_G = +155.5 ns
Note that τ_W - τ_E = 414.7 ns, Wanda ages 414.7 ns more than Elise
during their journey around the Earth
I bet that Doctor Richard Hachel is unable to find τ_E and τ_W.
He can't calculate anything in the real world.
So he will flee the challenge as he always does.
--
Paul
https://paulba.no/