Re: The problem of relativistic synchronisation

Den 03.09.2024 12:03, skrev Richard Hachel:

 We have:
 tA(e1) = 0
tA'(e1)= 0
tA(e2) = 0.75 s

OK.
And we could add:
tA(e2)  = (d/v)⋅√(1−v²/c²) = 0.75 s
tB'(e2) = d/v = 1.25 s
tA'(e3) = (d/v)⋅√(1−v²/c²) = 0.75 s
tB(e3)  = d/v = 1.25 s

 And what's missing:
tA'(e2) = 2.25
 

This is nonsense, and demonstrates that you
don't know what an event is.
e2 is the event that clock A and clock B' are adjacent
   tA'(e2) is meaningless.
I think you should read the paper again:
https://paulba.no/pdf/Mutual_time_dilation.pdf

The problem with B is that B is in B, that is to say somewhere other than in the conjunction AA'.

Is the "conjunction of AA'" the same as event E1?
Why is it a problem that B isn't present at this event?

We have synchronized the watches, A and A', but how do we do it for B?

????????!!!!!!!!!!!!!!
How confused is it possible to be?
A and A' are moving at the speed v relative to each other,
so of course A and A' can never be synchronous.
Setting two clocks to the same value as they pass each other
isn't to make them synchronous, they will only show the same
time at the instant they are adjacent.

 Of course there are idiots, like Python, who will say, we just have to synchronize anyhow. But they are crazy. Don't worry, we are waiting for them, we will burn them all.

Yes, there are idiots, and you are one of them. Python is not.

 There are two main ways to synchronize B and B', namely the synchronize on A and A' by noting tB(e1)=-1 and tB'(e1)=-1;

Good grief!
What the hell is tB(e1)=-1 and tB'(e1)=-1 supposed to mean?
LEARN WHAT AN EVENT IS.
The rest is mindless babble!

or either in practicing M type synchronization (Einstein synchronization),
noting tB(e1)=0 and tB'(e1)=0.
We are going to use Einstein synchronization to please Jean-Pierre.
For synchronization on AA', and not on M(R) and M'(R'), it will suffice to add Δt=-1.
We then have:

tB(e1)=0       {-1}
tB'(e1)=0      {-1}
tB(e2)=0.75    {-0.25}
tB'(e2)=0.25   {-0.75)
 We are now going to annoy Jean-Pierre,

I think Jean-Pierre is pleased to see that all he
has said about you is correct.

add the e3 event which is the conjunction BB'
which will happen at a certain time.
We apparently have:
tA(e3)= 0.50
tA'(e3)= 1.50
tB(e3)= -1.50 tB'(3)= -0.50
 For these last two data, we notice that they are negative, but that's normal.
 For B and for B', the synchronization is done after the conjunction BB'.
 Thank you for your attention.

R.H.
 

Above I asked you to read my paper again.
https://paulba.no/pdf/Mutual_time_dilation.pdf
FORGET IT!
You are clearly too ignorant and incompetent to understand it.
As you so convincingly have demonstrated!
--
Paul
https://paulba.no/