Re: Sync two clocks

Le 20/08/2024 à 04:26, hitlong@yahoo.com (gharnagel) a écrit :

On Tue, 20 Aug 2024 0:35:42 +0000, Richard Hachel wrote:

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Le 20/08/2024 à 01:33, hitlong@yahoo.com (gharnagel) a écrit :

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If tAB = tBA, then Paul's procedure works.  If tAB <> tBA,
then your point M method won't work either.

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 If we synchronize on an abstract point M placed at an equal
distance from A, B, C, D, E, we obtain for E a plane of the
present time where A, B,C,D and E are simultaneously located.

 Richard, Richard, Richard!  If tAB <> tBA, your method won't
work  Breath, blow, and THINK!  Given
 A ___________ M ___________ B
 If tAB <> tBA, then tAM <> tMB and A and B won't be synchronized.
 If, OTOH tMA = tMB, then tAB = tBA.

 You will never be able to synchronize two watches placed in different places with each other.
It is impossible.
The notion of "present time plane" is an abstract notion.
The present universe that is simultaneous with A is not the same as the one that is simultaneous with B and will never be the same whatever world of synchronization we can propose.
If you place M on a perpendicular bisector of AB, and you send a beep to A and B, their clocks will start running.
They will simultaneously start running FOR M.
But between them the relativity of the notion of simultaneity will mean that for A, B will have started running later, and, reciprocally B will accuse A of having started running later.
The reciprocal delay between A and B will be t=AB/c.
The notion of present time is relative.
It is still incredible that you cannot understand this.
It's 2024 and I'm still not surrounded by such a level of morons who are absolutely incapable of understanding what I'm saying.
But I don't even ask for people to believe me or not, although my intellectual strength allows me to do so on this point...
I only ask AT LEAST that people understand what I'm saying, and apparently, that seems impossible to a human mind...
But what's going on? ? ?
R.H.