Re: Sync two clocks

Den 23.08.2024 13:30, skrev Richard Hachel:

Le 23/08/2024 à 10:55, Mikko a écrit :

On 2024-08-23 05:41:50 +0000, Thomas Heger said:
 

Am Mittwoch000021, 21.08.2024 um 20:42 schrieb Paul.B.Andersen:

>
Richard, read your watch NOW. Write down the time nn:nn:nn.
The time nn:nn:nn is a proper time (read off a clock), it is
invariant, not depending on frame of reference.
>
Nobody can have another opinion of what time YOU read of YOUR watch.

>
This is not, what 'invariant' means in the context of relativity.

 Yes, it is.
 

Meant is, that time would not change, if you switch from one frame of reference to another.

 No, it means that whatever is called "invariant" is the same for all
frames. In the current case, the number wirtten on the paper is invariant.
 Mikko

 Here is yet another proof of what I am saying, and of the need to re-explain things correctly.

Do you mean that the fact that Tomas Heger doesn't know what
"invariant" means, is a proof of the need to re-explain
my statement correctly?
My statement was:
" Richard, read your watch NOW. Write down the time nn:nn:nn.
   The time nn:nn:nn is a proper time (read off a clock), it is
   invariant, not depending on frame of reference.
   Nobody can have another opinion of what time YOU read of YOUR watch."
Both "proper time" and "invariant" are explained in the text.
Exactly what do you not understand?
What is needed to be re-explained correctly?
--
Paul
https://paulba.no/