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Am Dienstag000027, 27.08.2024 um 11:58 schrieb Python:This is EXACTLY what is "under dispute".Le 27/08/2024 à 07:32, Thomas Heger a écrit :That was all not under dispute.Am Montag000026, 26.08.2024 um 09:06 schrieb Mikko:>
...>Relativity requires mutally symmetric methods. So if you synchronize clock B with clock A, this must come to the same result, as if you would synchronize clock A with clock B.>
No, it does not mutually symmetric methods. Such methods make the
presentation of the theory easier but do not affect the theory.
Einstein chose a symmetric method because otherwise his text would
be harder to read and understand.
The very word 'relativity' requires mutually symmetric perspectives.
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This goes like this:
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you stand there, I stand here and I see you.
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Now the opposite should also be possible, but from your perspective.
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This means: you see me, while you would call yourself 'I', your own location 'here' and mine 'there'.
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This would give:
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you stand there, I stand here and I see you (but said by you and from your point of view).
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Since both perspectives are of equal rights, we need to accept both views as valid, hence need mutually symmetric perspectives.
>>But this requirement was not fullfilled in Einstein's scheme, because Einstein didn't take delay into consideration.>
So you say but cannot prove.
Negative statements are difficult to prove.
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But I can ask you, to prove the opposite and prove, that you failed.
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So: where exactly did Einstein take delay into consideration in his 1905 paper??
In paragraph I.1 in Einstein's 1905 article you can read :
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(*) 2AB/(t'_A - t_A) = c
(**) t_B - t_A = t'_A - t_B
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In a setup with two mutually at rest clocks at position A and B in
a given system of reference. --> and <-- represents a light signal
emission/reception, all time values are recorded by both clocks at
time or receptions/re-emission:
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Step 1:
A--> B
t_A
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Step 2:
A -->B
t_B
A <--B
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Step 3:
A<-- B
t'_A
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So if you read the only equations in paragraph I.1,
assuming clocks are synchronized (which is the point of
this paragraph: state what it MEANS to be synchronized):
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(*) 2AB/(t'_A - t_A) = c
(**) t_B - t_A = t'_A - t_B
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t_B - t_A is a *delay* (between emission at A and reception at B)
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t_'A - t_B is a *delay* (between emission at B and reception at A)
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t'A - t_A is a *delay* (round trip time *delay* for a light signal
going from A to B bounced back to A)
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From (*) you can get : t'_A - t_A = 2AB/c so another way to
describe the same *delay* : twice the distance AB divided by c.
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Clearly such a *delay* is present in paragraph I.1. THREE times
as a term in an equation and ONCE as a term you can obtain by
ONE step of basic algebra.
Sure, these equation would allow tro calculate the delay.Absolutely not. As soon as t_A, t_B and t'_A are recorded their
(despite t_B and t_A' would be unknown at the remote side 'B')
But anyhow..It is a clear consequence of Einstein's method. If you apply it to
The problem was, that Einstein never used this value of the delay to compensate the timing value at the local side.
If you - for instance - peep through a large telescope and look at a large clock on the Moon and see the clock show e.g. 12:00:00:00 GMT, then you would see a time too early, because your own clock would show 12:00:01:00 GMT.
Now both clocks are actually in synch, even if the received view of the remote clock shows a different time then the local clock on Earth.This is completely unrelated to Einstein's procedure. There is no
But Einstein failed to mention the required correction of the remote signal by adding the delay to the received time value.When you turn the checking procedure into a synchronization procedure
This can only be interpreted, as if he didn't wanted to do that and leave the timing signal as received (what was wrong!!!).This *would* be wrong, right. But you're interpretation is in direct
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