Re: I dare to relativists to explain local time: t-vx/c²

Den 05.10.2024 19:32, skrev rhertz:

Explain this:
 1905 EINSTEIN'S MODIFIED LORENTZ TRANSFORMS
t' = γ (t - vx/c²)
x' = γ (x - vt)
 IF
 v = 11 Km/sec
x = 400 Km
 γ = 1.00000000067222

  γ = 1.00000000067315 ≈ 1.000000000673

  t' ≈ t - 48.89 nsec

wrong, see below

 48.89 nanoseconds meaning WHAT?

That your calculation is wrong.
You do know that the Lorentz transform is
a coordinate transformation, or don't you?
If the coordinates of an event are x = 400 km, t = t seconds
in the un-primed frame, then the coordinates  of the event
in the primed frame are:
  t' = (1.00000000067315⋅t - 48.96e-9) second
  x' = (400000.0002692 - 11000.0000074⋅t) meter
Note that t is a number you failed to define.

   Worse yet.

Is anything bad?

 IF x' = 0, then x = vt
 t' = γ (t - vx/c²) = γ (t - v²/c² t) = t/γ

Or generally:
  if x' is constant then dt'/dt = 1/γ
  if x is constant then dt/dt' = 1/γ
A clock which is stationary in a frame of reference will
be measured to run slow in a frame of reference which is
moving relative to the clock.

 t' = 0.999999998655556 t (now t' run slower than t!)

Yes, because the clock is stationary in the primed frame.
See:
https://paulba.no/pdf/Mutual_time_dilation.pdf

 Any explanations about these numerical examples of
the ridiculous results when applying SR?

There are no ridiculous results.
That Richard Hertz finds SR to be ridiculous doesn't
change the fact that SR is thoroughly experimentally
tested and never is falsified.
Some of the experimental evidence:
https://paulba.no/paper/index.html
That Richard Hertz find SR to be ridiculous does however have
the consequence that he has to claim that all physicist born
after 1900 are frauds and member of a MAFFIA.
If they were not, Richard Hertz would be wrong, which
according to Richard Hertz is impossible.
Hilarious, no? :-D
--
Paul
https://paulba.no/