Re: Want to prove E=mc²? University labs should try this!

On Wed, 20 Nov 2024 4:37:18 +0000, rhertz wrote:

On Wed, 20 Nov 2024 3:54:10 +0000, ProkaryoticCaspaseHomolog wrote:
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On Wed, 20 Nov 2024 0:48:23 +0000, gharnagel wrote:

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Given than dielectric coatings don't work here, a realistic reflection
coefficient for aluminum foil would be around 0.85 or so, so you won't
have a great build-up of power level inside your ball.
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The system will reach steady-state after a relatively short period of
time. If 5 watts is pumped in, the ball will radiate 5 watts of energy
at steady state. The emissivity will affect the final temperature that
the ball will reach, but figures like 167650K for 0.001" walls are
completely unrealistic numbers. The accumulated warmth should probably
be detectable by a person with sensitive fingers.
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Certainly you won't need to wait 72 hours to get your negative results.
Most of the time will be spent pumping down your high-vacuum system,
evaporating your "getter" to tie up the last bits of gas, etc.

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You refuse to accept an elementary fact, clearly stated by me in this
thread. Why? Maybe because you're not the EE/physicist that you claim to
be and you're just an amateur playing with science as a hobby.
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Get this for once:
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THE SYSTEM WILL NEVER REACH INTERNAL EQUILIBRIUM!

I said "steady-state", not equilibrium.

That is IMPOSSIBLE because I'd be pumping ENERGY non-stop, forever if
necessary. Can you get this, please?

Of course I understand that.
What you don't seem to understand is the distinction between steady-
state and equilibrium. Look it up.

THERE IS NO AMPLIFICATION OF LASER POWER, AND NEVER WAS MEANT TO HAPPEN.

Of course not. Especially with a reflection coefficient of around
0.85 or so.

WHAT HAPPEN IS A CONTINUOUS FEED OF ENERGY!. If you CAN'T SEE IT, then
substitute the 5W laser by a hose POURING WATER INSIDE THE CAVITY. Some
water falls out, but most remain UNTIL THE CAVITY IS FULL OF IT.
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When will it happen with the water analogy? Don't know/don't care.

Steady-state, not equilibrium.

The only reason by which I used three days to fill the cavity up is
because A LONGER PERIOD would accumulate much more perturbations and
external interferences, complicating the statistical processing of the
electrical signal that IS LINEARLY PROPORTIONAL to the accumulation of
energy inside the cavity.

What accumulation? The shell gradually rises in temperature until
the energy losses equals the energy input. How long this takes to
happen depends on the mass of the shell. For a thin shell, it won't
take long. For a thick shell, it could be a while. But you were
arguing on the basis of aluminum foil thickness, a few grams of
material.

If you REFUSE to understand this, I advise you to go back to college or
high school, where you could re-learn elementary logic and arithmetic.
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Say no more.

You are arguing from a position of ignorance here. Sorry.