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On Fri, 22 Nov 2024 20:30:39 +0000, Paul B. Andersen wrote:I'm sure that you didn't mean what you wrote.
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<snip all the history of your life. You didn't read my disclaimer>
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>Bottom line:>
It doesn't matter how you put energy into a closed cavity.
In the cavity there will be a black body radiation with
temperature equal to the temperature of the walls.
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The reflectivity, albedo or colour of the inner surface
of the cavity are irrelevant. The radiation in the cavity
will always be black body radiation.
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Make a hole in your cavity, and you have a perfect
black body radiation source.
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Its temperature will not be very high, though-
>>>
Now smile, asshole.
:-D
It is not a BB radiation source!
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You ignored the fact that the heat goes away from the cavity. It doesn't
remain neither inside nor outside. It's eliminated by cooling
mechanisms, as I wrote as an initial condition. Read all the posts.
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There is no light energy left within the cavity, nor heat energy outside
it. You better think again about it.
You also ignored my post apologizing to all people that participated inNote the length of Paul's post. In all probability, he started his
this thread. That makes you a bigger ASSHOLE than what I thought.
Now, start thinking in my NEXT IDEA:Just for fun, I calculated the mass difference between a new and a
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Willing to try to prove/disprove E=mc² at a macroscopic level, I'll
think of an experiment that incorporates electromagnetic oscillations
passing through the cavity, which will be converted in a CAPACITOR, by
cutting it in halves and isolating them with a thin ring.
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What I propose to MEASURE is the changes in the frequency of the LC
oscillator, within a time window of about 3 msec, which repeats
permanently.
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I'll use a relationship between mass and capacitance for the cavity,
with frequency around 1 Mhz or greater.
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It was a failed idea for an experiment, but there are OTHER WAYS to
check E=mc² at a macroscopic level, without resorting to nuclear energy
crap (Kg evaporated vs. energy provided), or else.
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