Re: Understanding the theory of special relativity

Den 18.01.2025 20:56, skrev Richard Hachel:

Le 18/01/2025 à 20:25, "Paul.B.Andersen" a écrit :
 

Stella is in a rocket and is co-located with Terrence when
she starts her rocket engine and accelerates at 1 c/year
away from Terrence for 2.25 year on her clock.
Then she turns her rocket around and accelerates at 1 c/year
towards Terrence for 4.5 years.
Then she turns her rocket around and accelerates (brakes) at 1 c/year
away from Terrence for 2.25 years.
 The important point is:
 When Stella is back, Terrence and Stella are co-located and
stationary to each other, and both can see both clocks which are
side by side.
 Terrence can see that his watch shows tau_T
and Stella's watch shows tau_S.
 Stella can see that her watch shows tau_S
and Terrence's clock shows tau_T.

 I've always said it, you're absolutely right,
the two times don't match.
 Stella looks at her watch, and she sees that her watch marks 9 years.
 She shows her watch to Terrence, and asks him what he sees, and he answers: "Your watch marks nine years".
 I don't see where the difficulty is.
 On the other hand, Terrence asks Stella, and you, what do you see on my watch, and she answers your watch marks 13.5 years.
 I don't understand how you can see a difficulty there.

We agree, there are no difficulties.

 It's the notion of the relativity of time.
 The only thing that opposes us is the way you calculate the ratio of the two watches, because you make a colossal error by using an incorrect integration taught by the theorists, and which gives you a smaller proper time, or a larger improper time.

We do not agree about the actual numbers.
I tell what SR predicts, you tell what Hachel predicts.
The important point is that we agree that:
Terrence's watch shows tau_T and Stella's watch shows tau_S,
tau_T > tau_S and both can see both watches.

Finally, you should not confuse chronotropy and the passage of time on watches.
 The relationship between Tr and To is a relationship of chronotropy.
 The time that passes on watches is not ONLY that, you have to take into account universal anisochrony, as well as the distances traveled by watches (and not just their relative speed).
 This is what makes it so that although the mechanisms of watches have always turned according to the same reciprocity, each one sees the other which turns less quickly in its internal mechanism, and this explains, as in the Langevin paradox, that however in the end, the two watches do not correspond, while the reciprocity of the internal beats is perfect.
 It is anisochrony that will actually induce the shift, not chronotropy.
 I have told you this 50 times.
 You do not, but then not at all, make the effort to understand me,
stuck in the idea that physicists cannot be wrong.
 Your bad faith becomes faith.
 

I can't see how all these words relate to the scenario at hand.
Here comes YOUR problem:
In the post I originally responded to, you, Richard Hachel wrote:
| "What is true is that, continuously, second after second,
|  in Terrence's frame of reference, the internal mechanism
|  of Stella's watch will beat less quickly."
OK. This is your explanation for why tau_T > tau_S.
According to Richard hachel:
  "Stella looks at her watch, and she sees that her watch marks 9 years.
   She shows her watch to Terrence, and asks him what he sees, and he
   answers: "Your watch marks nine years".
   On the other hand, Terrence asks Stella, what do you see
   on my watch, and she answers your watch marks 13.5 years.
But you also wrote:

"But what is also true is that the laws of physics are the same  in all frames of reference, and that the effects of physics
 are reciprocal by permutation of observer. For Stella it is  the opposite that is true. For her, it is the internal mechanism
 of Terrence's watch that beats constantly less quickly, and this
 during his journey."

Doesn't this mean that Stella should see that Terrence watch
shows less than her watch?
But you said:
  "Stella looks at her watch, and she sees that her watch marks 9 years.
   Terrence asks Stella, what do you see on my watch,
   and she answers your watch marks 13.5 years."
How can Stella see that Terrence watch has two different readings at
the same time?
Please explain.
-----------------------------------------
A word about frames of reference.
The phrase "to be in different frames" is nonsense.
We both are in my rest frame.
I am stationary, and you are probably moving.
We both are in your rest frame.
You are stationary, and I am probably moving.
Saying "we are in different frames" sounds like we are in
different worlds, with different realities.
But we are in the same world, the real world with one reality.
What's true in Terrence's rest frame is true in Stella's rest frame.
There is but one world and one reality.
Remember this in your response.
--
Paul
https://paulba.no/