Re: Division by zero

Liste des GroupesRevenir à sp relativity 
Sujet : Re: Division by zero
De : mikko.levanto (at) *nospam* iki.fi (Mikko)
Groupes : sci.physics.relativity
Date : 03. Feb 2025, 16:20:09
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On 2025-02-03 08:14:10 +0000, Thomas Heger said:

Am Sonntag000002, 02.02.2025 um 10:38 schrieb Mikko:
 
Hi NG
 I'm actually not really certain, but found an error in Einstein's 'On the electrodynamics of moving bodies' which is quite serious.
  See page six, roughly in the middle:
 There we find an equation, which says this:
 ∂τ/∂y= 0
 Do you mean on page 899 (9th page of the article) in §3?
The operation is not division but a partial derivative.
 τ was the name of the time coordinate in k and also the name of a function, which was meant as coordinate transformation between K and k.
 The time coordinate of an event in K has also a value in respect to k, hence time t of K should belong to the parameters of this function τ.
 But y should not, because the velocity along the y-axis was assumed to be zero and the axes of y and eta are assumed to remain parallel.
 So we had a function of time tau, which is 'vertical' upon the value zero of y.
 In my view, such a function would VERY steep, hence ∂τ/∂y= infinity (and not zero!)
 
For me seemingly ∂y/∂τ= 0 was meant, but ∂τ/∂y= 0 was written.
 That "seemingly" is only possible if you don't understand the text
you are attempting to discuss.
 The topic at the point is to discuss how τ is determined from x, y, z, and t.
...
 This is actually not true, because Einstein wrote this:
 " We first define τ as a function of x', y, z, and t. ..."
No need to revise my comment. The problem was to determine τ from x, y, z,
and t. The variable x' is just an intermediate step in that process.

The meaning of x' was also not defined properly and I'm still chewing on the problem to estimate, which interpretation is actually correct.
The definition x' was x' = x - vt, leaving no room for interpretations.

As far as I can tell, Einstein had this setting in mind:
  From the origin of the moving system k a light beam is emitted and moves along the x/xsi axis towards a mirror at position x', which is stationary in K, and gets reflected back from there to its origin at the center of k.
The title of §3 indicates otherwise. In particular, there is no light
and no mirror in the discussion around the formula ∂τ/∂y = 0.
--
Mikko

Date Sujet#  Auteur
1 Feb 25 * Division by zero28Thomas Heger
1 Feb 25 +* Re: Division by zero24Mikko
2 Feb 25 i+* Re: Division by zero5Ross Finlayson
2 Feb 25 ii`* Re: Division by zero4Thomas Heger
2 Feb 25 ii +* Re: Division by zero2Mikko
3 Feb 25 ii i`- Re: Division by zero1Paul.B.Andersen
2 Feb 25 ii `- Re: Division by zero (0, 1, infinity)1Ross Finlayson
2 Feb 25 i`* Re: Division by zero18Thomas Heger
2 Feb 25 i +* Re: Division by zero7Thomas Heger
2 Feb 25 i i`* Re: Division by zero6Mikko
3 Feb 25 i i `* Re: Division by zero5Thomas Heger
3 Feb 25 i i  `* Re: Division by zero4Mikko
4 Feb 25 i i   `* Re: Division by zero3Thomas Heger
5 Feb 25 i i    `* Re: Division by zero2Mikko
5 Feb 25 i i     `- Re: Division by zero1Thomas Heger
2 Feb 25 i `* Re: Division by zero10Mikko
3 Feb 25 i  `* Re: Division by zero9Thomas Heger
3 Feb 25 i   +* Re: Division by zero2Athel Cornish-Bowden
3 Feb 25 i   i`- Re: Division by zero1Thomas Heger
3 Feb 25 i   `* Re: Division by zero6Mikko
3 Feb 25 i    +- Re: Division by zero1Maciej Wozniak
4 Feb 25 i    `* Re: Division by zero4Thomas Heger
4 Feb 25 i     `* Re: Division by zero3Mikko
4 Feb 25 i      +- Re: Division by zero1Maciej Wozniak
5 Feb 25 i      `- Re: Division by zero1Thomas Heger
1 Feb 25 +* Re: Division by zero2J. J. Lodder
2 Feb 25 i`- Re: Division by zero1Ross Finlayson
20 Feb 25 `- Re: Division by zero1JanPB

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