Sujet : Re: Positrons
De : ram (at) *nospam* zedat.fu-berlin.de (Stefan Ram)
Groupes : sci.physics.relativityDate : 08. Jul 2025, 20:57:02
Autres entêtes
Organisation : Stefan Ram
Message-ID : <mass-20250708205259@ram.dialup.fu-berlin.de>
References : 1 2 3 4 5 6 7
"Paul.B.Andersen" <
relativity@paulba.no> wrote or quoted:
E_1 = E_0 "Energy is conserved"
p_1 = p_0 "momentum is conserved"
m_1 < m_0 "mass is converted into energy"
Please explain why these three assumptions are not compatible with:
e⁺ + e⁻ → γ + γ
Well, "energy", "momentum", and "mass" are /vague terms/. One needs
to specify the energy (momentum, mass) /of what/ one refers to.
If one would try to correct the vagueness of "mass is converted into
energy" by saying, "the mass of 'γ + γ' is smaller than the mass
of 'e⁺ + e⁻'" (thereby saying "of what"), then this would be wrong.
m₀ = 2m, m₁ = 0
Well, this is the same point: It's too vague because the system
is not specified. The mass of what system is "m_0"? The mass of
what system is "m_1"? So, to quote Dirac, it's not even wrong!
But, if I assume that m_0 is the mass of "e⁺ + e⁻", then it's
wrong, because when they move in their COG system m_0 > 2m
(assuming m to be the mass of an e⁺ or e⁻ in its COG system)
if they are moving with a non-zero speed in the COG.
And m_1 surely is larger than 2*0 (two times the mass of
a photon). For one illustration: The mass of a gluon is 0.
Yet the kinetic energy of gluons make up for 37 percent of the
/mass/ of a proton. You don't get this value of .37*m_p if you
take the mass of each gluon in isolation and then sum them up.
No, wait, it was Pauli, not Dirac!