Sujet : Re: Positrons
De : ram (at) *nospam* zedat.fu-berlin.de (Stefan Ram)
Groupes : sci.physics.relativityDate : 09. Jul 2025, 20:53:08
Autres entêtes
Organisation : Stefan Ram
Message-ID : <hydrogen-20250709205201@ram.dialup.fu-berlin.de>
References : 1 2 3 4 5 6 7 8 9 10
ram@zedat.fu-berlin.de (Stefan Ram) wrote or quoted:
To get into this mindset just think about how the mass of an atom
of hydrogen is smaller than the mass of the proton and electron
taken in isolation. This would be another example where the
mass of a combined system differs from the sum of the masses of its
components.
The binding energy of hydrogen is "-13.6 eV".
It is the sum of the potential energy and the kinetic energy
of the electron and is part of the mass energy of hydrogen.
I take this calculation from the World-Wide Web, but might
have added typos when converting it to plain text:
At the mean radius a_B = 0.528 × 10^{−10} m, the potential energy
of the pair is:
1 e^2
U = − ----- --- = −4.36 × 10^{−18} J = −27.2 eV.
4πϵ_o a_B
The kinetic energy is half this value, and agrees with the classical
result for a particle in uniform circular motion:
mv^2 1 e^2 1 1 e^2
---- = ----- ----- => - mv^2 = ----- ---.
a_B 4πϵ_o a_B^2 2 8πϵ_o a_B
So the binding energy is: E = K + U = −13.6 eV.