Sujet : Re: Incompleteness of Cantor's enumeration of the rational numbers
De : james.g.burns (at) *nospam* att.net (Jim Burns)
Groupes : sci.mathDate : 11. Nov 2024, 19:23:49
Autres entรชtes
Organisation : A noiseless patient Spider
Message-ID : <1fca3a53-1cb4-4fd2-85b6-85e9b69ca23b@att.net>
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User-Agent : Mozilla Thunderbird
On 11/11/2024 3:41 AM, WM wrote:
On 10.11.2024 18:49, Jim Burns wrote:
On 11/10/2024 4:35 AM, WM wrote:
On 10.11.2024 00:27, Jim Burns wrote:
In the first case, with the not.changing sets,
a finite ๐๐ฒ๐พ๐๐ฒ๐ป๐ฐ๐ฒ of ๐ฐ๐น๐ฎ๐ถ๐บ๐ which
ย ย has only true.or.not.first.false ๐ฐ๐น๐ฎ๐ถ๐บ๐
has only true ๐ฐ๐น๐ฎ๐ถ๐บ๐.
>
But it
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"It" refers to who or what?
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To that finite ๐๐ฒ๐พ๐๐ฒ๐ป๐ฐ๐ฒ.
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But it will never complete
an infinite set of claims.
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We do not need an infinite ๐๐ฒ๐พ๐๐ฒ๐ป๐ฐ๐ฒ of ๐ฐ๐น๐ฎ๐ถ๐บ๐ completed.
We do not want an infinite ๐๐ฒ๐พ๐๐ฒ๐ป๐ฐ๐ฒ of ๐ฐ๐น๐ฎ๐ถ๐บ๐ completed.
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But you claim that
_all_ fractions are in bijection with
all natural numbers,
don't you?
Yes, I claim that.
This is one ๐ฐ๐น๐ฎ๐ถ๐บ:
โ All fractions are in bijection with
โ all natural numbers.
We can peel that claim apart,
truthfully and finitely saying what it means, and
we can situate ๐ถ๐ in a finite ๐๐ฒ๐พ๐๐ฒ๐ป๐ฐ๐ฒ of ๐ฐ๐น๐ฎ๐ถ๐บ๐,
each ๐ฐ๐น๐ฎ๐ถ๐บ of which is true.or.not.first.false.
Such a ๐๐ฒ๐พ๐๐ฒ๐ป๐ฐ๐ฒ has only true ๐ฐ๐น๐ฎ๐ถ๐บ๐.
That ๐ฐ๐น๐ฎ๐ถ๐บ, being in that ๐๐ฒ๐พ๐๐ฒ๐ป๐ฐ๐ฒ, is a true ๐ฐ๐น๐ฎ๐ถ๐บ.
โ I have been ๐ณ๐น๐ถ๐ฝ๐ฝ๐ถ๐ป๐ด back ๐ฎ๐ป๐ฑ ๐ณ๐ผ๐ฟ๐๐ต between ๐ณ๐ผ๐ป๐๐,
โ in an attempt to visibly mark a distinction between
โ claims as bearers of meaning and
โ ๐ฐ๐น๐ฎ๐ถ๐บ๐ as objects, as vibrations in the air,
โ smears of colored bear fat on a cave wall, bits, or pixels.
โ
โ Finite sequences of smears of bear fat have
โ certain properties which we ("we" very broadly)
โ have learned to use in our exploration of infinity.
โ
โ Note: that's _finite_ sequences.
โ Issues involving Scrooge McDuck and Disappearing Bob
โ do not come into play for these properties.
It will forever remain in the status nascendi.
Therefore
irrelevant for actual or completed infinity.
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A finite ๐๐ฒ๐พ๐๐ฒ๐ป๐ฐ๐ฒ of ๐ฐ๐น๐ฎ๐ถ๐บ๐, each of which
is true.or.not.first.false,
will forever remain
a finite ๐๐ฒ๐พ๐๐ฒ๐ป๐ฐ๐ฒ of ๐ฐ๐น๐ฎ๐ถ๐บ๐, each of which
is true.or.not.first.false.
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Therefore
such a sequence does not entitle you
to claim infinite mappings.
No.
Such a ๐๐ฒ๐พ๐๐ฒ๐ป๐ฐ๐ฒ does entitle me.
A finite ๐๐ฒ๐พ๐๐ฒ๐ป๐ฐ๐ฒ of ๐ฐ๐น๐ฎ๐ถ๐บ๐, each of which
is true.or.not.first.false,
is
a finite ๐๐ฒ๐พ๐๐ฒ๐ป๐ฐ๐ฒ of ๐ฐ๐น๐ฎ๐ถ๐บ๐, each of which
is true.
Infinite sets can correspond to
other infinite sets which,
without much thought about infinity,
would seem to be a different "size".
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But they cannot become such sets.
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Our sets do not change.
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My intervals I(n) = [n - 1/10, n + 1/10]
must be translated to all the midpoints
1/1, 1/2, 2/1, 1/3, 2/2, 3/1, 1/4, 2/3, 3/2, 4/1, 1/5,
2/4, 3/3, 4/2, 5/1, 1/6, 2/5, 3/4, 4/3, 5/2, 6/1, ...
if you want to contradict my claim.
Your ๐ฐ๐น๐ฎ๐ถ๐บ๐ start with "Sets change".
If we are in the same discussion,
they are already contradicted at that point,
If we aren't in same discussion,
I don't see how to respond sensibly.
End.of.debate, I guess? If there ever was a debate?