Re: Any honest person that knows the x86 language can see...

On 7/29/2024 2:38 PM, Fred. Zwarts wrote:

Op 29.jul.2024 om 21:35 schreef olcott:

On 7/29/2024 2:18 PM, Fred. Zwarts wrote:

Op 29.jul.2024 om 16:07 schreef olcott:

HHH(Infinite_Recursion) and HHH(DDD) show the same non-halting
behavior pattern in their derived execution traces of their
inputs.
>
Correct emulation is defined as emulating the machine language
input according to the x86 semantics specified by this input.
>
For DDD correctly emulated by HHH this includes HHH emulating
itself emulating DDD according to the x86 semantics of itself.
>
HHH(DDD) shows the exact same execution trace behavior pattern
as HHH(Infinite_Recursion) where 3-4 instructions are repeated
with no conditional branch instructions in this trace that could
prevent them from endlessly repeating.
>
void Infinite_Recursion()
{
   Infinite_Recursion();
}

>
No, the HHH that aborts after N cycles has a similar behaviour as
>

>
So you don't even know that infinite recursion is non-halting behavior.
You can go back and try again on this same post I am not looking at
anything else that you say.

 Non halting is only in your dreams. HHH that aborts halts. Dreams are no substitute for logic.
 

void Infinite_Recursion()
{
   Infinite_Recursion();
}
In other words you are confirming that you
honestly believe the above function halts?
Do you understand that Halts means terminates normally
on its own without being forced to stop running?
void Infinite_Loop()
{
   HERE: goto HERE;
}
Do you understand that yanking the power cord out of
the wall does not cause Infinite_Loop() to halt?
--
Copyright 2024 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer