Liste des Groupes | Revenir à theory |
On 5/13/2024 9:31 PM, Richard Damon wrote:No, I said that because there is not path to p, it would need to be false, but that was based on the assumption that it could exist.On 5/13/24 10:03 PM, olcott wrote:On 5/15/2024 8:39 PM, Richard Damon wrote:>>
Remember, p defined as ~True(L, p) is BY DEFINITION a truth bearer, as True must return a Truth Value for all inputs, and ~ a truth valus is always the other truth value.
>
Can a sequence of true preserving operations applied to expressions
that are stipulated to be true derive p?
> Which has NOTHING to do with the problem with True(L, p)
> being true when p is defined in L as ~True(L, p)
*YOU ALREADY AGREED THAT True(L, p) IS FALSE*
Right, but that has nothing to do with the problem with True(L, p) being false, because, since p in L is ~True(L, p) so that make True(L, ~false) which is True(L, true) false, which is incorrrect.>On 5/15/2024 7:52 PM, Richard Damon wrote:
No, so True(L, p) is false
and thus ~True(L, p) is true.
>>>
Can a sequence of true preserving operations applied to expressions
that are stipulated to be true derive ~p?
> Which has NOTHING to do with the above,
> as we never refered to False(L,p).
*YOU ALREADY AGREED THAT false(L, p) IS FALSE*
right, by your definitions, True(L, p) is False, but that means that True(L, true) is false, so your system is broken.>Please try and keep these two thoughts together at the same time
No, so False(L, p) is false,
>
*I need to make another point that depends on both of them*
*YOU ALREADY AGREED THAT True(L, p) IS FALSE*
*YOU ALREADY AGREED THAT false(L, p) IS FALSE*
Les messages affichés proviennent d'usenet.