Sujet : A simulating halt decider applied to the The Peter Linz Turing Machine description ⟨Ĥ⟩
De : polcott333 (at) *nospam* gmail.com (olcott)
Groupes : comp.theory sci.logicDate : 27. May 2024, 00:47:16
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <v30e5l$3lerc$1@dont-email.me>
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On 5/26/2024 3:20 PM, Richard Damon wrote:
On 5/26/24 3:14 PM, olcott wrote:
When Ĥ is applied to ⟨Ĥ⟩
Ĥ.q0 ⟨Ĥ⟩ ⊢* embedded_H ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qy ∞
Ĥ.q0 ⟨Ĥ⟩ ⊢* embedded_H ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn
>
When we see that ⟨Ĥ⟩ ⟨Ĥ⟩ correctly simulated by embedded_H in an
infinite number of steps cannot possibly reach its own simulated
final state of ⟨Ĥ.qn⟩ and halt then we correctly deduce that the
same thing applies when simulating halt decider embedded_H correctly
simulates less than an infinite number of steps of ⟨Ĥ⟩ ⟨Ĥ⟩.
>
Nope.
Since we are talking about Turing Machines, your stipulated POOP definitions go away,
https://www.liarparadox.org/Linz_Proof.pdf*Simplified the notation for Ĥ on the top of page three*
and put back in the qy state shown in figure 12.2
When Ĥ is applied to ⟨Ĥ⟩
Ĥ.q0 ⟨Ĥ⟩ ⊢* embedded_H ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qy ∞
Ĥ.q0 ⟨Ĥ⟩ ⊢* embedded_H ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn
Ĥ copies its own Turing machine description: ⟨Ĥ⟩
then invokes embedded_H that simulates ⟨Ĥ⟩ with ⟨Ĥ⟩ as input.
It is an easily verified fact that ⟨Ĥ⟩ ⟨Ĥ⟩ correctly simulated by embedded_H cannot possibly reach its own simulated final state of
⟨Ĥ.qn⟩ in any finite sequence of steps.
*If you want to lie about this or fail to understand this*
*irrefutable truth that only makes yourself look foolish*
Any academicians reading this post will further conclude
that your insults and ad hominem attacks are quite pathetic.
-- Copyright 2024 Olcott "Talent hits a target no one else can hit; Geniushits a target no one else can see." Arthur Schopenhauer