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On 6/4/2024 11:23 AM, Fred. Zwarts wrote:It seems you are unable to read. I told you already that Mike's reply has as a consequence that both HH and DD go in recursive recursion, so, neither of them reaches its final state.Op 04.jun.2024 om 18:13 schreef olcott:Clearly you did not pay close enough attention to Mike Terry'sProof that executed HH(DD,DD) and simulated HH(DD,DD) simulate DD>
correctly. This proof requires expert knowledge of the C programming
language and the x86 programming language.
>
With this expertise it is easy to confirm that both the directly
executed HH(DD,DD) and the simulated executed HH(DD,DD) simulate the
steps of DD exactly the way that the x86 machine language specifies.
>
If one also has expertise on the mapping from the C source code to the
x86 assembly language then one also confirms that the x86 version of
DD is exactly what the C source-code specifies.
>
01 int DD(int (*x)())
02 {
03 int Halt_Status = HH(x, x);
04 if (Halt_Status)
05 HERE: goto HERE;
06 return Halt_Status;
07 }
08
09 int main()
10 {
11 Output("Input_Halts = ", HH(DD,DD));
12 }
>
_DD()
[00001db2] 55 push ebp
[00001db3] 8bec mov ebp,esp
[00001db5] 51 push ecx
[00001db6] 8b4508 mov eax,[ebp+08]
[00001db9] 50 push eax ; push DD
[00001dba] 8b4d08 mov ecx,[ebp+08]
[00001dbd] 51 push ecx ; push DD
[00001dbe] e8bff5ffff call 00001382 ; call HH
[00001dc3] 83c408 add esp,+08
[00001dc6] 8945fc mov [ebp-04],eax
[00001dc9] 837dfc00 cmp dword [ebp-04],+00
[00001dcd] 7402 jz 00001dd1
[00001dcf] ebfe jmp 00001dcf
[00001dd1] 8b45fc mov eax,[ebp-04]
[00001dd4] 8be5 mov esp,ebp
[00001dd6] 5d pop ebp
[00001dd7] c3 ret
Size in bytes:(0038) [00001dd7]
>
machine stack stack machine assembly
address address data code language
======== ======== ======== ========= =============
[00001de2][00103292][00000000] 55 push ebp
[00001de3][00103292][00000000] 8bec mov ebp,esp
[00001de5][0010328e][00001db2] 68b21d0000 push 00001db2 ; push DD
[00001dea][0010328a][00001db2] 68b21d0000 push 00001db2 ; push DD
[00001def][00103286][00001df4] e88ef5ffff call 00001382 ; call HH
New slave_stack at:103336
>
Begin Local Halt Decider Simulation Execution Trace Stored at:11333e
[00001db2][0011332a][0011332e] 55 push ebp ; DD line 01
[00001db3][0011332a][0011332e] 8bec mov ebp,esp ; DD line 02
[00001db5][00113326][001032fa] 51 push ecx ; DD line 03
[00001db6][00113326][001032fa] 8b4508 mov eax,[ebp+08] ; DD line 04
[00001db9][00113322][00001db2] 50 push eax ; push DD
[00001dba][00113322][00001db2] 8b4d08 mov ecx,[ebp+08] ; DD line 06
[00001dbd][0011331e][00001db2] 51 push ecx ; push DD
[00001dbe][0011331a][00001dc3] e8bff5ffff call 00001382 ; call HH
New slave_stack at:14dd5e
[00001db2][0015dd52][0015dd56] 55 push ebp ; DD line 01
[00001db3][0015dd52][0015dd56] 8bec mov ebp,esp ; DD line 02
[00001db5][0015dd4e][0014dd22] 51 push ecx ; DD line 03
[00001db6][0015dd4e][0014dd22] 8b4508 mov eax,[ebp+08] ; DD line 04
[00001db9][0015dd4a][00001db2] 50 push eax ; push DD
[00001dba][0015dd4a][00001db2] 8b4d08 mov ecx,[ebp+08] ; DD line 06
[00001dbd][0015dd46][00001db2] 51 push ecx ; push DD
[00001dbe][0015dd42][00001dc3] e8bff5ffff call 00001382 ; call HH
Local Halt Decider: Infinite Recursion Detected Simulation Stopped
>
[00001df4][00103292][00000000] 83c408 add esp,+08
[00001df7][0010328e][00000000] 50 push eax
[00001df8][0010328a][00000743] 6843070000 push 00000743
[00001dfd][0010328a][00000743] e8a0e9ffff call 000007a2
Input_Halts = 0
[00001e02][00103292][00000000] 83c408 add esp,+08
[00001e05][00103292][00000000] eb79 jmp 00001e80
[00001e80][00103292][00000000] 33c0 xor eax,eax
[00001e82][00103296][00000018] 5d pop ebp
[00001e83][0010329a][00000000] c3 ret
Number of Instructions Executed(16829) == 251 Pages
>
It is clearly a false negative.
>
Olcott defends a simulating halt decider H. The problem with it is, that it introduces another halting problem: The H itself does not halt when simulated by itself. This cause false negatives: many functions are now diagnosed by H to be non-halting only by the mere fact that they call H, even if their direct execution does halt.
reply to you and/or you lack the required prerequisite skill
in the C programming language and/or the x86 language.
It never has mattered at all that HH(DD,DD) indirectly aborts
a simulation of itself by aborting its simulation of DD.
The directly executed HH sees that neither DD nor its simulation
of itself can possibly halt and that <is> its correct basis for
rejecting DD as non-halting.
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