Liste des Groupes | Revenir à theory |
On 7/4/24 6:33 PM, olcott wrote:It must depend on the decider looking at it or we are requiredOn 7/4/2024 5:21 PM, Richard Damon wrote:Nope, doesn't work. Particularly for Turing Machines.On 7/4/24 2:32 PM, olcott wrote:>On 7/4/2024 1:17 PM, Richard Damon wrote:>On 7/4/24 2:04 PM, olcott wrote:><MIT Professor Sipser agreed to ONLY these verbatim words 10/13/2022>>
If simulating halt decider H correctly simulates its input D
until H correctly determines that its simulated D would never
stop running unless aborted then
>
H can abort its simulation of D and correctly report that D
specifies a non-halting sequence of configurations.
</MIT Professor Sipser agreed to ONLY these verbatim words 10/13/2022>
>
On 10/14/2022 7:44 PM, Ben Bacarisse wrote:
> I don't think that is the shell game. PO really /has/ an H (it's
> trivial to do for this one case) that correctly determines that P(P)
> *would* never stop running *unless* aborted.
...
> But H determines (correctly) that D would not halt if it were not
> halted. That much is a truism.
>
Ben clearly agrees that the above criteria have been met,
yet feels that professor Sipser was tricked into agreeing
that this means that:
H can abort its simulation of D and correctly report that D
specifies a non-halting sequence of configurations.
>
I spent two years deriving those words that Professor Sipser
agreed with. It seems to me that every software engineer would
agree that the second part is logically entailed by the first part.
>
You mean you WASTED two years and set a trap for your self that you fell into.
>
The problem is that Ben is adopting your definitions that professor Sipser is not using.
>
Ben agrees that my criteria have been met according to their
exact words. If you want to lie about that I won't talk to
you again.
>
Which meant different things, so not the same.
>
The biggest problem is your H/P interlocking program pair is something outside the normal scope of Computation theory.
>
The way you have built your Deicder/Decider combination isn't actualy within the definition of normal Computaiton Theory, as that would have Decider as a totally independent program from the program it is deciding on.
>
Your H and D aren't that sort of thing because they are interwined into a single memory space, and even share code.
>
This makes some things possible to do about the pair that can not be done if they were independent programs, like H being able to detect that D calls itself (but not copies of itself, which is why you don't allow those copies, as that breasks your lie).
>
Ever heard of string comparison?
H can detect that D calls copies of itself.
That merely makes the details more complex.
The problem is that the seperate compliation and linking with the resultant different address makes the byte pattern for the code not necessarily a duplicate.
When you consider that the input is antagonistic, it can also intentionally make alterations that do not change the outward behavior, but do change the byte code.
I seem to remember that it has been proven that, in general, the identification of an equivalent copy of yourself is uncomputable.
We went over this before, and you could never understand it.
>Nope. Your basic structure can not be converted back into a pair of Turing Machihes, showing it isn't based on actual Computations.Another of the big effect of thins, is that the way you defined it, D actually does have access to the decider that is going to decide it (if we follow your rule and name the decider H). This can turn what used to be an independent fully defined program P into a dependent program template.>
The key issue is that by my basis structure that applies equally
to DD correctly simulated by HH as it applies to ⟨Ĥ⟩ correctly
simulated by embedded_H is that the paradoxical decision point
cannot be reached. This converts the "impossible" problem into a
difficult one.
>But your criteria isn't a legal critieria. The "Behavior" of the input must be an objective property of just that input, and thus can not be something that depends on the decider looking at it.Undet THAT condition, Ben agreed that yoUr H could conclude that no version of H could simulate the version of D that uses it, to its final state. Since P is a template, and not a program, it doesn't have the normal Objective definition of behavior, and thus your subjective one might need to be used, even with its problems.>
>
The key point that you must acknowledge before continuing is
that the criteria is met for H/D. I can't tolerate one more
reply where you deny this.
Thus, the direct execution of the program the input repreesents is what is consider the "behavior of an input" that represents a program.--
And thus, since DDD() Halts, HHH(DDD) saying "non-halting" can not be correct.
The question of can HHH simulate its input to a final state is just an incorrect question, and your logic that looks at different inputs to try to make you claim is just invalid.
>When you asked Professor Sipser, The H will be a SPECIFIC decider, and the D will be a specific input that doesn't change, and thus DOES have an objective behavior (that of directly running it, or completely simulating it) and only if H can determine that this OBJECTIVE definition is met, can it abort. Of course, due the relationship in the construction of D, the H that it was built from can NEVER make that correct determination, as if it does, then D will halt and thus H could not have made the determination.>
>
The fact that you don't understand this just shows how little you understand the theory, or it seems, programming in general.
Les messages affichés proviennent d'usenet.