Liste des Groupes | Revenir à theory |
On 7/7/2024 1:41 AM, Fred. Zwarts wrote:Yes. This shows that the simulation is incorrect.Op 06.jul.2024 om 21:14 schreef olcott:Correctly is measured by the semantics of the x86 language.On 7/6/2024 1:55 PM, Fred. Zwarts wrote:>Op 06.jul.2024 om 18:30 schreef olcott:>On 7/6/2024 10:29 AM, Fred. Zwarts wrote:>>>
So, why do you disagree that the x86 code specifies an HHH that aborts and halts?
Dishonest dodge of changing the subject. This is called
the strawman deception and is a favorite tactic of liars.
Irrelevant text ignored. You talked about x86, therefore continuing to talk about x86 is not a change of subject.
I know you have difficulties to recognize the truth, so I do not feel offended, because: 'Don't assume somebody is wilfully wrong, if incompetence could be an explanation, as well.'
>>>
If you sufficiently understand the semantics of the x86
language then you can see that the call to HHH(DDD) from
DDD simulated according to the semantics of the x86 language
cannot possibly return.
I understand enough of it to see that it cannot possibly return, because HHH cannot possibly simulate itself correctly.
According to the semantics of the x86 language IS IS IMPOSSIBLE
FOR DDD SIMULATED BY HHH TO RETURN AND IT IS EQUALLY IMPOSSIBLE
FOR THE HHH(DDD) CALLED BY DDD SIMULATED BY HHH TO RETURN.
Therefore, you should agree that HHH cannot possibly simulate itself correctly.
This specifies that when DDD is correctly simulated by HHH
calls emulated HHH(DDD) that this call cannot return.
You smash a bottle on the ground. No matter how much youSimilarly, HHH cannot possibly simulate itself correctly, no matter how much you want it to be correct, it is incorrect. It always aborts too soon and therefore misses the fact that the simulated HHH is one cycle away from its abort and return.
want the bottle to hold water it will not hold water.
But you seem to reason like that. The simulation is incorrect, but you prefer it to be correct. It is just as wrong.That is what the semantics of the x86 teach you.A correct simulation is what-so-ever-the Hell that the x86
There is no disagreement about the semantics of the x86, if you see that it means that HHH cannot possibly reach its own 'ret' instruction, therefore, the simulation cannot possibly be correct.
>
machine code of HHH/DDD specifies even if this code starts
WW III. Correct is not measured by what you would like to
see or what you expect to happen. Correct is only measured
by the behavior that the code specifies.
When I say that 2 + 3 = 5 you are not free to dislike this
result and prefer or expect 2 + 3 = 7.
Les messages affichés proviennent d'usenet.