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On 6/3/2025 10:02 PM, dbush wrote:And what is the CONTRADICTION?On 6/3/2025 10:58 PM, olcott wrote:Likewise with halt deciders that are required to reportOn 6/3/2025 9:46 PM, dbush wrote:>On 6/3/2025 10:34 PM, olcott wrote:>On 6/3/2025 9:12 PM, dbush wrote:>>>
Given any algorithm (i.e. a fixed immutable sequence of instructions) X described as <X> with input Y:
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A solution to the halting problem is an algorithm H that computes the following mapping:
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(<X>,Y) maps to 1 if and only if X(Y) halts when executed directly
(<X>,Y) maps to 0 if and only if X(Y) does not halt when executed directly
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Yes there is no algorithm that does that
Excellent!
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Let The Record Show
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That Peter Olcott
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Has *EXPLICITLY* admitted
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That no algorithm H exists that meets the above requirements, which is precisely the theorem that the halting problem proofs prove.
In the exact same way that there is no set of all set
that contain themselves. ZFC did not solve Russell's
Paradox as much as it showed that Russell's Paradox
was anchored in an incoherent foundation, now called
naive set theory.
Which arose because the axioms of naive set theory created a contradiction.
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on the behavior of directly executed Turing machines.
Directly executed Turing machines are outside of theThen so is mathematics, as "numbers" can't be given to Turing Machines, only representations of them.
domain of every Turing machine decider.
Which you just continue to lie to, so proving that you are just a pathological liar.In contrast, the axioms of computation theory do *not* create a contradiction. It simply follows from those axioms that no H exists the meets the above requirements, which is a completely valid conclusion.*Claude.ai seems to be the smartest bot about computation*
https://claude.ai/share/48aab578-aec3-44a5-8bb3-6851e0f8b02e
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