Sujet : Re: Relativistic aberration
De : dd (at) *nospam* sirrd.gr (Conard Demakis)
Groupes : sci.math sci.physics sci.physics.relativitySuivi-à : sci.math sci.physics sci.physics.relativityDate : 03. Aug 2024, 01:02:26
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Richard Hachel wrote:
Le 02/08/2024 à 21:49, "Paul.B.Andersen" a écrit :
Den 01.08.2024 23:03, skrev Richard Hachel:
The rocket will see the supernova an angle 12.7⁰ from the x-axis.
(From Earth the supernova is seen in the direction 37⁰ from the x-axis)
Absolutely. We have cos α = 12000/15000 = 0.8 ---> α ~ 37°
Ans we have cos α' = 40000/41000 = 0.9756 ---> α' ~ 12.7°
Note :
cos α' = (cosα+v/c)/(1+cosα.v/c) cos α' = (0.8+0.8)/(1+0.8*0.8)=0.9756
All is correct.
illucid, show those angles without a calculator. It's an arccos getting 1
at 0, to 0 at pi/2 then -1 at pi. lol.
𝗪𝗵𝗮𝘁_𝗵𝗮𝗽𝗽𝗲𝗻𝘀_𝘄𝗵𝗲𝗻_𝘆𝗼𝘂_𝗰𝗼𝗺𝗯𝗶𝗻𝗲_𝗔𝗹𝘂𝗺𝗶𝗻𝘂𝗺_𝗮𝗻𝗱_𝗠𝗲𝗿𝗰𝘂𝗿𝘆
https://old.bi%74%63%68ute.com/%76%69%64eo/Ydfl1HIF9ZaO
Re: Relativistic aberration