Re: The problem of relativistic synchronisation

Le 01/09/2024 à 19:41, "Paul.B.Andersen" a écrit :

Den 01.09.2024 16:13, skrev Richard Hachel:

AB (at rest) = 3.10^8m
A'B' (at rest) = 3.10^8m
>
v=0.8c tA(e2)= ?

tA(e2)=0.75 sec

Chicken!

 No YOU chicken !
 tA (e1)= 0
 tA'(e1)= 0
 tA (e2)= 0.75  But now, we have to go further. Do you want to remain a chicken?

No.

Why, Paul?

Because I don't want to be a chicken anymore. I want to be a brave man.

OK, Paul.
So we're going to continue, because it's very important.
A sees the segment AB coming towards him, and when A' crosses A, which is event e1, A starts his watch. tA(e1)=0
Then A observes that B' is approaching him at high speed, and stops his watch when B crosses him, this is event e2, and we note tA(e2)=0.75.
There is an interval of 0.75 seconds between e1 and e2.
But, however, Paul is a chicken. And he's going to run away (prophecy of Nostradamus).
"Great King Hachel speak usenet
Afraid chicken run away".
For 0.75 seconds, B' rushes toward A.
Two questions that today represent two of the biggest questions in the entire existence of sci.physics?relativity
1. At what apparent (i.e. APPARENT) speed does A apprehend B' rushing toward him?
Chicken!
2. What is the apparent distance traveled by B' during the interval noted by the watch?
Chicken! Chicken!
R.H.