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Am Montag000019, 19.08.2024 um 14:56 schrieb Python:
I take as example two spaceships in 1 lightseconds distance, which are called A and B.AB = 1 lightsecond
Both have a HUGE clock strapped to that spaceship and use a VERY HUGE telescope to read the clock of the other ship."Now" for A.
Now clock A shows 12 o'clock and zero seconds.
Ship B reads this at time 12 o'clock plus 1 second,Si sa montre est synchronisée en convention Eisntein.
but turns the own clock (showing 12 o'clock plus one seconds) back by one second.Dans ce cas, B est parfaitement synchronisé sur A, c'est à dire que B "vit" exactement dans la
Now the observer of ship A reads the clock from ship B and reads 12 o'clock plus zero seconds, while the own clock shows 12 o'clock plus one seconds.No!
This is regarded as an error and the own clocks as being ahead, hence it was turned back to 12 o'clock plus zero seconds.
This is seen from ship B, where the own clock shows actually 12 o'clock plus one second. This is corrected by adjustment of one second, by which that clock is turned backwards.
This could go on forever, while both clocks would stand still.
But certainly this is not what you would call 'synchronization'.
TH
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