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On 4/13/24 1:36 AM, Richard Hachel wrote:Can you help further explain for the rest of us why"If two different observers travel an identical path in equal>
observable times, then their proper times will necessarily be equal.
Yes, of course.
>
My response differs from others because I interpret your context
differently.
>
Since you mention "proper times", your context must be relativity; it
does not matter whether SR or GR, because "travel an identical path"
means they travel along a single worldline through spacetime -- i.e.
they are always co-located and co-moving, so of course their elapsed
proper times are equal (counting from any event on their worldline).
>
Your "in equal observable times" is redundant. For any
observer this directly follows from them following the
same worldline through spacetime.
>
Note this is essentially the first time I agree with Hachel. I doubt
that he understands why what he wrote is actually correct, because he
followed it with a bunch of obfuscatory nonsense.
>[... enormous amount of gibberish ignored.]>
Tom Roberts
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