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>No, it's not. It's only a paradox when part of the operation is
Langevin's paradox.
The Langevin paradox is a very serious criticism against the theory of
relativity.
[Verbal bobbling deleted]Dr. Hachel is wrong, along with all those who conveniently forget about
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What was the grievance?
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If the twin of the stars returns younger in the frame of reference of
the twin who remained on earth, then the twin who remained on earth,
if we apply the reciprocity of effects, and Doctor Richard Hachel says
that we must use this notion of reciprocity,
very basis of logic, comes back older than the other. Which is both“No, no, you’re not thinking: you’re just being logical” – Niels Bohr
logical and absurd.
No one has ever been able to answer the question correctly andIncorrect assertion.
perfectly
[Self-aggrandizing verbage deleted]Incorrect assertion.
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The great problem facing the world's physicists is a problem of
confusion.
They confuse two notions: the notion of relativity of measured times,
and the notion of reciprocal relativity of chronotropies.
It's not the same thing.Not impossible.
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Hence the impossibility for them all to explain things coherently.
The relativity of the measured times will show that over a journey of 24[Corrections made].
light years, carried out at v=0.8c, Terrence will age by 30 years.
It's very simple: x=v.t, i.e. t=x/v and 24[/]0.8=30
But when Stella returns, she will only be 18 years old[er].
There is therefore an asymmetry, that is obvious, but it is on theNot everyone, and there is more than one way to skin a cat.
explanation of the asymmetry that everyone sinks into complete
ignorance.
Because we are confusing it with the notion of chronotropy, which isThen you have failed. Whether the entire path a semicircle, or just the
ANOTHER THING, and which can be defined by the internal functioning of
watches. On this, yes, the effect is symmetrical, reciprocal; each
watch, and throughout the entire journey, (including if I place a small
half-turn phase on a semi-circle with a preserved tangential speed of
0.8c), beats faster than the other watch, and the equation is constant
and reciprocal over the entire path: T2=T1/sqrt(1-v²/c²).
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This is true.
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But this only qualifies chronotropy, that is to say the internal
mechanism of watches, it is not the whole of the relativistic effect.
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This is not what we will ultimately measure.
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I can't explain it more clearly.
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