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Le 15/07/2024 à 13:27, "Paul.B.Andersen" a écrit :Why so many words to give the simple answer:Den 14.07.2024 23:11, skrev Richard Hachel:What does your theory predict the speed of the protons in the LHC is?But I have already answered you a thousand times.
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What is the measured speed of the protons in the LHC?
The observable, i.e. measurable, speed of the proton in the LHC is 0.999999989c.
I set Vo=0.999999989c.
It's still very simple to understand, and if you made more effort to achieve coherent discussions, we wouldn't be talking such banalities.
I just pointed out, even if it may seem very destabilizing, that this is only the observable, measured speed, but that it is not the deep reality of things.
You know very well that the measurement of the shadow of a building is not the measurement of the building itself. It depends on the position of the sun.
We have the same thing in relativity.
When we measure, in our frame of reference, the distances to be covered, we have a precise measurement to note.
But when we measure the time it takes to cover this distance, a huge illusion appears because apart from the rocket or the particle, which only have one watch, we are obliged to use two watches (even if we come back to the same physical watch, after a long journey, it is no longer really "the same watch").
Paul, breathe, exhale.
Measuring time with two watches placed in different places can only lead to temporal aberrations.
Speed being the quotient of distance over time, we will no longer have the same notion of speed. An illusion will appear since our way of measuring things becomes incorrect.
When you measure the observable speed Vo of your proton, you find Vo=0.999999989c but if you want to know the real speed
in the lab reference frame, you must convert (i.e. remove the bias from the measurement).
Vr=Vo/sqrt(1-Vo²/c²)
Conversely, if you know Vr, you use the reciprocal equation to find Vo.
Vo=Vr/sqrt(1+Vr²/c²)
The real speed of your proton (not the one you measure) is therefore Vr=6947c.
This is enormous speed.You failed to answer the second question.
If you know the mass of your proton, and if you know its momentum at this instant, you just need to use p=m.v
You will see that v, in reality, is Vr=6947c and not Vo=0.999999989c.
R.H.
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