Sujet : Re: The problem of relativistic synchronisation
De : relativity (at) *nospam* paulba.no (Paul.B.Andersen)
Groupes : sci.physics.relativityDate : 01. Sep 2024, 18:42:26
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <vb28vm$1i5d6$2@dont-email.me>
References : 1 2 3 4 5 6 7 8 9 10 11
User-Agent : Mozilla Thunderbird
Den 01.09.2024 16:13, skrev Richard Hachel:
Le 01/09/2024 à 14:27, "Paul.B.Andersen" a écrit :
Den 01.09.2024 13:25, skrev Richard Hachel:
Nous allons maintenant donner des précisions numériques.
>
AB (at rest) = 3.10^8m
A'B' (at rest) = 3.10^8m
>
v=0.8c tA(e2)= ?
>
https://paulba.no/pdf/Mutual_time_dilation.pdf
>
Still a problem with equation (1)?
>
t₂ = 0.75052 second
I do not accept your answer.
In stead of making a fool of yourself like this,
you can rather respond to the more interesting part of
the post you were responding to.
Please, answer the simple question below:
When the train leaves Nantes, you see the watch on the railway station
showing 8:32, and you start your stop watch. When you arrive in Berlin,
you see the watch on the railway station showing 20:41. You stop your
stop watch which show that the duration of the journey was 12h 9m.
The question:
-------------
Why is the difference between the Berlin clock at arrival and
the Nantes clock at departure equal to the duration of your journey,
20:41 - 8:32 = 12h 9m ?
You will keep fleeing, won't you? Chicken!
-- Paulhttps://paulba.no/